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3.5x^2-6.8x+1.5=0
a = 3.5; b = -6.8; c = +1.5;
Δ = b2-4ac
Δ = -6.82-4·3.5·1.5
Δ = 25.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.8)-\sqrt{25.24}}{2*3.5}=\frac{6.8-\sqrt{25.24}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.8)+\sqrt{25.24}}{2*3.5}=\frac{6.8+\sqrt{25.24}}{7} $
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